in triangle abc, DE parallel to BC prove ab/ ad = ac / ec Question in triangle abc, DE parallel to BC prove ab/ ad = ac / ec in progress 0 Math Sadie 3 weeks 2021-10-04T00:51:35+00:00 2021-10-04T00:51:35+00:00 2 Answers 0 views 0

## Answers ( )

Step-by-step explanation:Proof: From the figure , ABC and ADE we have

ABC = ADE …….( Corresponding angles are equal.)

ACB = AED…….( Corresponding angles are equal.)

Then by AA axiom of similarity we can conclude that ABC ADE

We know that corresponding sides of a similar triangles are proportional.

∴ AB / AD = AC / AE

⇒ ((AD + DB) / AD) = ((AE / EC) / AE) …. (∵ AB = AD + DB and AC = AE + EC)

⇒ 1 + (DB / AD) = 1 + (EC / AE)

⇒ (DB / AD) = EC / AE

⇒ (AD / DB) = AE / EC …..(by taking reciprocals)

Hence, AD / DB = AE / EC

Answer:Please type the question again..

It is not clear..

Whether DE is mid point??